10=(r^4-1)/(r^2-1)

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Solution for 10=(r^4-1)/(r^2-1) equation:


D( r )

r^2-1 = 0

r^2-1 = 0

r^2-1 = 0

1*r^2 = 1 // : 1

r^2 = 1

r^2 = 1 // ^ 1/2

abs(r) = 1

r = 1 or r = -1

r in (-oo:-1) U (-1:1) U (1:+oo)

10 = (r^4-1)/(r^2-1) // - (r^4-1)/(r^2-1)

10-((r^4-1)/(r^2-1)) = 0

(-1*(r^4-1))/(r^2-1)+10 = 0

(-1*(r^4-1))/(r^2-1)+(10*(r^2-1))/(r^2-1) = 0

10*(r^2-1)-1*(r^4-1) = 0

10*r^2-r^4-9 = 0

10*r^2-r^4-9 = 0

10*r^2-r^4-9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

r = 1

10*r^2-r^4-9 = 0

1

r-1

9*r-r^3-r^2+9

10*r^2-r^4-9

r-1

r^4-r^3

10*r^2-r^3-9

r^3-r^2

9*r^2-9

9*r-9*r^2

9*r-9

9-9*r

0

9*r-r^3-r^2+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

r = 1

9*r-r^3-r^2+9 = 16

1

-1

r = -1

9*r-r^3-r^2+9 = 0

-1

r+1

9-r^2

9*r-r^3-r^2+9

r+1

r^3+r^2

9*r+9

-9*r-9

0

9-r^2 = 0

DELTA = 0^2-(-1*4*9)

DELTA = 36

DELTA > 0

r = (36^(1/2)+0)/(-1*2) or r = (0-36^(1/2))/(-1*2)

r = -3 or r = 3

r in { -3, 3, 1, -1}

(r+3)*(r-3)*(r-1)*(r+1) = 0

((r+3)*(r-3)*(r-1)*(r+1))/(r^2-1) = 0

((r+3)*(r-3)*(r-1)*(r+1))/(r^2-1) = 0 // * r^2-1

(r+3)*(r-3)*(r-1)*(r+1) = 0

( r+1 )

r+1 = 0 // - 1

r = -1

( r+3 )

r+3 = 0 // - 3

r = -3

( r-1 )

r-1 = 0 // + 1

r = 1

( r-3 )

r-3 = 0 // + 3

r = 3

r in { -1}

r in { 1}

r in { -3, 3 }

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